> (I assume that in your example "a0000" and "aa" => c00aa, that really should have been a00aa)
Yes , thanks for noticing. On Fri, Sep 1, 2017 at 11:18 PM, Irv Kalb <i...@furrypants.com> wrote: > > > On Sep 1, 2017, at 10:13 AM, Ganesh Pal <ganesh1...@gmail.com> wrote: > > > > In the fixed length string i.e "a0000",last 4 bits i.e "0000" should be > > replaced by the user provided value ( the value is between 0001 + f f f > f ) > > . I intend to form final_string using a fixed_string and an user > provided > > user_string > > > > > > Example: > > > > fixed_string = "a0000" > > user_string ='1' > > > > final string = fixed_string and user_string > > > > Example : > > > > "a0000" and "1" => a0001 > > > > "a0000" and "aa" => c00aa > > > > > > PS : "and" this is not logical and it's just for example > > > > If I concatenation using + or += or it's append the value at the end of > > the string > > > >>>> "a0000" + "1" ===> expected was a0001 > > 'a00001' > > > > > > > > I am on python 2.7 and Linux , any ideas that you recommend to handle > > this > > > > > > Regards, > > Ganesh > > > > Here's a little function that should it it for you. > > (I assume that in your example "a0000" and "aa" => c00aa, that really > should have been a00aa) > > This should work for any size fixed_string and user_string (as long as the > user_string is not longer than the fixed_string) > > def mergeStrings(fixed_string, user_string): > nCharsInFixedString = len(fixed_string) > nCharsInUserString = len(user_string) > > nCharsToGetFromFixedString = nCharsInFixedString - nCharsInUserString > > finalString = fixed_string[:nCharsToGetFromFixedString] + user_string > > return finalString > > Irv > > -- > https://mail.python.org/mailman/listinfo/python-list > -- https://mail.python.org/mailman/listinfo/python-list
