Peter Otten writes:
...
> def edges(items):
> first = last = next(items)
> for last in items:
> pass
> return [first, last]
...
> However, this is infested with for loops. Therefore
...
> I don't immediately see what to do about the for loop in edges(), so
> I'll use the traditional cop-out: Removing the last loop is left as an
> exercise...
In the spirit of the exercise:
def sekond(x, y):
return y
def edges(items): # where items is a non-empty iterator
first = next(items)
last = functools.reduce(sekond, items, first)
return [first, last]
Of course, right?
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