On Friday, May 26, 2017 at 5:02:55 PM UTC+5:30, Cecil Westerhof wrote:
> To check if Firefox is running I use:
> if not 'firefox' in [i.name() for i in list(process_iter())]:
>
> It probably could be made more efficient, because it can stop when it
> finds the first instance.
>
> But know I switched to Debian and there firefox is called firefox-esr.
> So I should use:
> re.search('^firefox', 'firefox-esr')
>
> Is there a way to rewrite
> [i.name() for i in list(process_iter())]
>
> so that it returns True when there is a i.name() that matches and
> False otherwise?
> And is it possible to stop processing the list when it found a match?
'in' operator is lazily evaluated if its rhs is an iterable (it looks)
So I expect you can replace
if not 'firefox' in [i.name() for i in list(process_iter())]:
with
if not 'firefox' in (i.name() for i in list(process_iter())]):
As this sessions indicates
>>> def myiter():
... yield 1
... yield 2
... print ("yielded 2")
... yield 3
... print("yielded 3")
...
# basic behavior
>>> for x in myiter(): print(x)
...
1
2
yielded 2
3
yielded 3
# does not reach 2 3
>>> 1 in myiter()
True
# reaches 2 but not the print after
>>> 2 in myiter()
True
# reaches 3 but not the print after
>>> 3 in myiter()
yielded 2
True
# exhausts the iterator
>>> 4 in myiter()
yielded 2
yielded 3
False
>>>
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