On Wed, May 17, 2017 at 4:44 PM, <serap...@gmail.com> wrote: > When using feedparpser object as below, it only contains 25 items, how can i > have all contents? > for example, > d= feedparser.parse('http://newyork.craigslist.org/stp/index.rss') > print(len(d['entries'][i]['summary'])) > > result is 25....
Have you looked at the actual file delivered by craigslist? It seems to have only 25 items in it. It's not feedparser's limit. ChrisA -- https://mail.python.org/mailman/listinfo/python-list