> Why would you expect a single dictionary? You're doing 3 separate matches!
>
> correct, I didn't knew how to combine it all the patterns
You could just combine the patterns as alternatives:
>
> # The alternatives are matched repeatedly. The final '.' alternative
> # will consume a character if none of the previous subpatterns match,
> # ready for the next repeat.
> subpatterns = [r'(?P<Block>(\d+,\d+,\d+:\d+))',
> r'(?P<p_owner>([0-9a-fA-F]+:[0-9a-fA-F]+:[0-9a-fA-F]+::HEAD))',
>
> r'(?P<a_owner>(owner:\s+[0-9a-fA-F]+:[0-9a-fA-F]+:[0-9a-fA-F]+::HEAD))',
> '.']
> pattern = '(%s)*' % '|'.join(subpatterns)
> match = re.search(pattern, line)
> print ' ', match.groupdict()
>
>
There seems to be some silly mistake after I added the above code. I
get "*sre_constants.error:
nothing to repeat "*
error
Sample code:
#!/usr/bin/python
import re
with open("/tmp/2.repo","r") as f:
for line in f:
result = re.search(r'MSG=attempt to record(.*)LINSNAP', line)
if result:
for subpattern in [r'(?P<Block>(\d+,\d+,\d+:\d+))',
r'(?P<p_owner>([0-9a-fA-F]+:[0-9a-fA-F]+:[0-9a-fA-F]+::HEAD))',
r'(?P<a_owner>(owner:\s+[0-9a-fA-F]+:[0-9a-fA-F]+:[0-9a-fA-F]+::HEAD))',
'.']:
regex = re.compile(subpattern)
pattern = '(%s)*' % '|'.join(subpattern)
match = re.search(pattern, line)
print ' ', match.groupdict()
Sample output:
yy-1# python final_01.py
Traceback (most recent call last):
File "final_01.py", line 18, in <module>
match = re.search(pattern, line)
File "/usr/local/lib/python2.7/re.py", line 146, in search
File "/usr/local/lib/python2.7/re.py", line 251, in _compile
*sre_constants.error: nothing to repeat*
The code looks fine but may be there is something to do with * , may be we
need to find a better way to escape * ?
> /tmp/final_01.py(17)<module>()
-> pattern = '(%s)*' % '|'.join(subpattern)
(Pdb) n
> /tmp/final_01.py(18)<module>()
-> match = re.search(pattern, line)
(Pdb) pattern
'((|?|P|<|B|l|o|c|k|>|(|\\|d|+|,|\\|d|+|,|\\|d|+|:|\\|d|+|)|))*'
(Pdb) n
error: error('n...repeat',)
Regards,
Ganesh
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