Russell E. Owen wrote:
> The "hash" function looks promising -- it prints out consistent values
> if I use it instead of "id" in the code above. Is it stable and unique?
> The documentation talks about "objects" again, which given the behavior
> of id makes me pretty nervous.
>
I dont know how the hash of a bound method is calculated,but as the
function of the method is a stable and referenced object and as
instances lives are in your hands,then an id(self)^id(self.meth.im_func)
should be a chance for that 'hash' function.
def methodId(boundMethod):
return id(boundMethod.im_self)^id(boundMethod.im_func)
class cls(object):
def __init__(self):
print methodId(self.meth1)
print methodId(self.meth2)
def meth1(self):
pass
def meth2(self):
pass
c = cls()
print methodId(c.meth1)
print methodId(c.meth2)
I think this is giving what you expected.
Regards Paolino
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