On Wed, 12 Apr 2017 01:08:07 -0700, jfong wrote:
> I have a list of list and like to expand each "list element" by
> appending a 1 and a 0 to it. For example, from "lr = [[1], [0]]" expand
> to "lr = [[1,1], [0,1], [1,0], [0,0]]".
>
> The following won't work:
>
> Python 3.4.4 (v3.4.4:737efcadf5a6, Dec 20 2015, 19:28:18) [MSC v.1600 32
> bit (Intel)] on win32 Type "help", "copyright", "credits" or "license"
> for more information.
>>>> lr = [[1], [0]]
>>>> lx = []
>>>> for i in range(len(lr)):
> ... lx[:] = lr[i]
> ... lx.append(0)
> ... lr[i].append(1)
> ... lr.append(lx)
> ...
>>>> lr
> [[1, 1], [0, 1], [0, 0], [0, 0]]
>>>>
>>>>
> But the following does:
>
>>>> lr = [[1], [0]]
>>>> lx = []
>>>> for i in range(len(lr)):
> ... lx = lr[i][:]
> ... lx.append(0)
> ... lr[i].append(1)
> ... lr.append(lx)
> ...
>>>> lr
> [[1, 1], [0, 1], [1, 0], [0, 0]]
>>>>
>>>>
> After stepping through the first one manually:
>
>>>> lr = [[1], [0]]
>>>> lx[:] = lr[0] lx.append(0)
>>>> lx
> [1, 0]
>>>> lr[0].append(1)
>>>> lr
> [[1, 1], [0]]
>>>> lr.append(lx)
>>>> lr
> [[1, 1], [0], [1, 0]]
>>>>
>>>>
> So far so good...
>
>>>> lx[:] = lr[1] lx.append(0)
>>>> lx
> [0, 0]
>>>> lr[1].append(1)
>>>> lr
> [[1, 1], [0, 1], [0, 0]]
>>>>
>>>>
> Woops! What's wrong?
>
> --Jach Fong
1st never* use range to step through items in a list
if you need the index as well as the item use Enumerate
a=[[1],[2]]
for i,x in enumerate(a):
a[i].append(0)
print a
* like all rules an experienced programmer may find a usage case where it
may be broken
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