On Thu, Mar 16, 2017 at 9:31 AM, MRAB <pyt...@mrabarnett.plus.com> wrote:
>> 3.2. If the carry bit from S1 is 1, the MSB of S1 and LSB of S0 are
>> inverted.
>> Points 2 and 3 are executed for all bytes, included in the calculation of
>> the CRC - from the first byte after BEG up to and including byte END.
>> 4. TR is loaded with 0 and point 3 is executed
>> 5. TR is loaded with 0 and point 3 is executed
>> 6. Byte S1 is transmitted
>> 7. Byte S0 is transmitted
>>
> [snip]
> Step 3 is a little unclear.
>
> Step 3.1 says to shift TR, but step 3.2 says to check the carry bit after
> shifting S1, which is zero initially, therefore the carry bit will be clear,
> therefore S1 and S0 won't have any bits inverted and will stay zero.
>

I think probably "if the carry bit from TR is 1" would make this all
make sense. Otherwise TR, which is the data payload, is completely
ignored.

ChrisA
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