On Thursday, March 2, 2017 at 11:27:34 AM UTC-5, Peter Otten wrote:
> Andrew Zyman wrote:
> .....
> .....
> > End result:
> > ll =[ [a,1], [b,2], [c,3], [blah, 1000, 'new value'] ]
>
> >>> outer = [["a", 1], ["b", 2], ["c", 3], ["blah", 1000]]
> >>> for inner in outer:
> ... if inner[0] == "blah":
> ... inner.append("new value")
thank you. this will do.
Just curious, is the above loop can be done in a one-liner?
> While this is what you are asking for it will get slower as the list grows.
> A better solution uses a dictionary:
> >>> lookup = {inner[0]: inner[1:] for inner in outer}
Yes, understood, i don't expect the list to grow above a few thousand entries.
But i do agree that utilizing the dict is more efficient.
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