i want to do some image processing using Django and now work and on the image
handling(donwloading/display) using Django. first on my task i dont want to
store that images on my server. but i have some problems.
that my code :
urls.py
from django.conf.urls import url
from . import views
urlpatterns = [
#url(r'^$',views.index, name='index'),
url(r'^$',views.calc, name='calc'),
]
file.html
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Title</title>
</head>
<body>
<form method="POST" enctype="multipart/form-data">
{% csrf_token %}
{{ form.as_p }}
<input type="button" value="Submit">
</form>
{{ flow_direction_uri.url }}
</body>
</html>
forms.py
from django import forms
class ImageUploadForm(forms.Form):
"""Image upload form."""
image = forms.ImageField()
views.py
from django.shortcuts import render
from django.shortcuts import render_to_response
from django.template import RequestContext
from pygeoprocessing import routing
from django import forms
from blog.forms import ImageUploadForm
def calc(request):
form = ImageUploadForm()
if request.method == "POST" and form.is_valid():
image_file = request.FILES['image']
form.save()
'''do something image process'''
'''and finaly i take that output in standalone python script out of
django'''
outpu1 = "outpu1.tif"
outpu2 = "outpu2.tif"
outpu3 = "outpu3.tif"
outpu4 = "outpu4.tif"
return render_to_response ('blog/calc.html', {'form':form,'output1':output1},
RequestContext(request))
and i take that error :
UnboundLocalError at /
local variable 'output1' referenced before assignment
but i thing so its not that error why if i change to response request to
{return render_to_response ('blog/calc.html', {'form':form},
RequestContext(request))
` dont show me that error i can see in the browser two buttons where i can
choose image from my files and submit button but i thing so that do nothing.
maybe to use html forms and no Django forms ?
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