Smith wrote:
> Hi all,
> could you do better?
> Thank you in advance
>
> link code:
> https://repl.it/FMin/8
Don't make it unnecessarily hard to find your code -- as long as it's small
you can include it into your mail
Given
> with open('partite.txt', 'r') as f:
> splitted = [(int(line.split("'")[0]), line) for line in f]
> splitted.sort()
> lsorted = [line for (m, line) in splitted]
> for z in lsorted:
> print(z)
>
with partite.txt looking like this
> 74' Kessie'
> 90' + 4' D'alessandro
> 51' Mchedlidze
> 54' Banega
> 56' Icardi
> 65' Icardi
> 14' Sau
Assuming you want to perform a numerical sort on the numbers before the '
you can just apply sorted
with open(...) as f:
print("".join(sorted(f))
as long as all number strings have the same length.
If that's not the case python's sorted() has decorate-sort-undecorate
capabilities built in -- no need to do it manually:
with open("partite.txt") as f:
by_number = sorted(f, key=lambda line: int(line.partition("'")[0]))
print("".join(by_number))
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