El lunes, 9 de enero de 2017, 14:09:09 (UTC+1), José Manuel Suárez Sierra
escribió:
> Hello, I am trying to make a code wich compares between 2 or several
> sequences (lists). It compares every element in a list with another list
> elements. For example, if we have a list_a=["a","b","c","d"] and
> list_b=["a","b"] I want to obtain a new list_c containing elements that match
> between these lists (a and b here), but, if for instance list_b were
> ["a","c"] the program must not store this data because they are not in same
> order.
>
> Said this, I wrote this code but it doesnt work:
>
> if __name__ == "__main__":
>
>
> def compare(a, b):
>
> i = 0
> j = 0
> c1 = []
>
> while a[i] == b[j]:
> c1.append(a[i])
> j = j+1
> i=i+1
>
> return c1
>
>
>
>
> cadena_1=raw_input("Introduce list 1 \n")
> cadena_2 = raw_input("Introduce list 2 \n")
>
>
> transf1=list(cad_1)
> transf2 = list(cad_2)
>
>
> print compare(transf1,transf2)
>
>
>
>
> Thank you
Thanks for your reply,
I wrote this code:
def comparar(cad1, cad2):
i = 0
j = 0
cad3 = []
k = True
for cad1[i] in cad1:
k = True
for cad2[j] in cad2:
while cad1[i] == cad2[j] and i<= len(cad1) and j <= len(cad2):
cad3.append(cad1[i])
i = i + 1
j = j + 1
if cad1[i] != cad2[j]:
k = False
i = i + 1
return cad3
This is a function, another important thing is the order of elements, it must
be ordered as it appears in one of the lists, in your example, my function must
return a list with elements 1,2,5 in that order.
I cant find my mistake in these function I wrote you above.
Thank you very much
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