On Saturday, January 7, 2017 at 12:26:04 PM UTC+5:30, Jussi Piitulainen wrote:
> Paul Rubin writes:
>
> > Peter Otten writes:
> >> How would you implement stopmin()?
> >
> > Use itertools.takewhile
>
> How? It consumes the crucial stop element:
>
> it = iter('what?')
> list(takewhile(str.isalpha, it)) # ==> ['w', 'h', 'a', 't']
> next(it, 42) # ==> 42
I was also wondering how…
In a lazy language (eg haskell) with non-strict foldr (reduce but rightwards)
supplied non-strict operator this is trivial.
ie in python idiom with reduce being right_reduce
reduce(operator.mul, [1,2,0,4,...], 1)
the reduction would stop at the 0
Not sure how to simulate this in a strict language like python
Making fold(r) non-strict by using generators is ok
How to pass a non-strict operator?
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