Nikhil Verma wrote:
> Hey guys
>
> What is the most optimal and pythonic solution forthis situation
>
> A = [{'person_id': '1', 'adop_count': '2'}, {'person_id': '3',
> 'adop_count': '4'}]
> *len(A) might be above 10L*
>
> B = [{'person_id': '1', 'village_id': '3'}, {'person_id': '3',
> 'village_id': '4'}]
> *len(B) might be above 20L*
>
>
> OutPut List should be
>
> C = B = [{'adop_count': '2', 'village_id': '3'}, {'adop_count': '4',
> 'village_id': '4'}]
>
> Thanks in advance
Build a lookup table that maps person_id to village_id:
>>> A = [{'person_id': '1', 'adop_count': '2'}, {'person_id': '3',
... 'adop_count': '4'}]
>>> B = [{'person_id': '1', 'village_id': '3'}, {'person_id': '3',
... 'village_id': '4'}]
>>> p2v = {item["person_id"]: item["village_id"] for item in B}
>>> assert len(B) == len(p2v), "duplicate person_id"
>>> import collections
>>> v2a = collections.defaultdict(int)
>>> for item in A:
... v2a[p2v[item["person_id"]]] += int(item["adop_count"])
...
>>> [{"adop_count": str(v), "village_id": k} for k, v in v2a.items()]
[{'adop_count': '4', 'village_id': '4'}, {'adop_count': '2', 'village_id':
'3'}]
If the data stems from a database you can run (untested)
select B.village_id, sum(A.adop_count) from A inner join B on A.person_id =
B.person_id;
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