On 2016-11-11 13:29, Peter Otten wrote:
> The same using update(), with a generator expression that avoids
> the intermediate dict:
>
> >>> dict1 = {'A': 'a', 'B': 'b', 'C': 'c'}
> >>> dict1.update((k, dict2[k]) for k in desired & dict1.keys() &
> dict2.keys())
Huh. Handy to file that new knowledge away. I'd not realized it
could take a 2-tuple iterable, but my previous example would then be
more cleanly written as
dict1.update((k,v) for k,v in dict.items() if k in desired)
But yes, certainly a couple edge cases depending on the dict
sizes, the size of the "desired" set, and what should happen in the
event dict2 (or "desired") has keys that dict1 doesn't.
-tkc
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