On 10/31/2016 03:09 PM, devers.meetthebadger.ja...@gmail.com wrote:
http://imgur.com/a/rfGhK#iVLQKSW
How do I code a function that returns a list of the first n elements of the
sequence defined in the link? I have no idea!!!!!
So far this is my best shot at it (the problem with it is that the n that i'm
subtracting or adding in the if/else part does not represent the element's
position, but just the n that I am plugging into the function):
def reca(n):
rlist=[0]
while len(rlist) < n:
if (rlist[-1]-n) > 0 and (rlist[-1]-n) not in rlist:
rlist.append(rlist[-1]-n)
else:
rlist.append(rlist[-1]+n)
return(rlist)
I'm not looking at your link or your code, just your description of the problem.
Paraphrased: "A list of the first n elements of a sequence"
No function necessary, just use slicing...
newlist = oldlist[:n]
list: [1,2,3,4,5,6,7,8,9,10][:5] gives [1,2,3,4,5]
tuple: (1,2,3,4,5,6,7,8,9,10)[:5] gives (1,2,3,4,5)
string: "Hello there"[:5] gives "Hello"
Works for sequences shorter than n as well, which gives the full (short)
sequence.
list: [1,2,3][:5] gives [1,2,3]
etc...
--
-=- Larry -=-
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