Hi Guys Try to connect to the smtp via smtplib.
The connection is down because the Firewall has not been open yet so the exception is something that should appear. Now I want to catch this timeout in case error happens in future. Here the exception trace. [2016-10-12 14:14:06,289] ERROR in app: Exception on /api/barredMSISDN [POST] Traceback (most recent call last): File "/usr/local/lib/python3.4/site-packages/flask/app.py", line 1988, in wsgi_app response = self.full_dispatch_request() File "/usr/local/lib/python3.4/site-packages/flask/app.py", line 1641, in full_dispatch_request rv = self.handle_user_exception(e) File "/usr/local/lib/python3.4/site-packages/flask/app.py", line 1544, in handle_user_exception reraise(exc_type, exc_value, tb) File "/usr/local/lib/python3.4/site-packages/flask/_compat.py", line 33, in reraise raise value File "/usr/local/lib/python3.4/site-packages/flask/app.py", line 1639, in full_dispatch_request rv = self.dispatch_request() File "/usr/local/lib/python3.4/site-packages/flask/app.py", line 1625, in dispatch_request return self.view_functions[rule.endpoint](**req.view_args) File "/root/main.py", line 34, in barredMSISDN smtp_con(http_json) File "/root/main.py", line 134, in smtp_con server = smtplib.SMTP('smtp.lebara.com') File "/usr/local/lib/python3.4/smtplib.py", line 242, in __init__ (code, msg) = self.connect(host, port) File "/usr/local/lib/python3.4/smtplib.py", line 321, in connect self.sock = self._get_socket(host, port, self.timeout) File "/usr/local/lib/python3.4/smtplib.py", line 292, in _get_socket self.source_address) File "/usr/local/lib/python3.4/socket.py", line 516, in create_connection raise err File "/usr/local/lib/python3.4/socket.py", line 507, in create_connection sock.connect(sa) TimeoutError: [Errno 110] Connection timed out How to catch such exception? ... have been trying with a lot of combinations (of course except the correct one :)) try: server.sendmail(sender, receivers, msg.as_string()) except Exception as e: <-- have try with many combinations here print("SMTP could not be contacted: %s",e) pass finally: server.quit() Joaquin This email is confidential and may be subject to privilege. If you are not the intended recipient, please do not copy or disclose its content but contact the sender immediately upon receipt. -- https://mail.python.org/mailman/listinfo/python-list