Gregory Ewing <greg.ew...@canterbury.ac.nz> writes:
> Steve D'Aprano wrote:
>
>> And (shamelessly using Python syntax) if I have a function:
>>
>> def spam(x):
>> print(x)
>> print(x+1)
>>
>> spam(time.sleep(60) or 1)
>
> You can't write that in Haskell, because Haskell's
> equivalent of print() is not a function (or at least
> it's not a function that ever returns), and neither
> is sleep().
I suppose it all depends on what "that" is exactly. Here is the closest
match I could come up with:
import Control.Concurrent
spam io = do x <- io;
print x;
print (x+1)
main = spam (do threadDelay (2*10^6); return 1)
It matches the Python in that the delay happens once. To get the
behaviour being hinted at (two delays) you need to re-bind the IO
action:
spam io = do x <- io;
print x;
x <- io;
print (x+1)
<snip>
--
Ben.
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