Am 10.09.16 um 05:12 schrieb dkole...@olearycomputers.com:
Hey;
Long term perl ahderent finally making the leap to python. From my reading,
python, for the most part, uses perl regex.. except, I can't seem to make it
work...
I have a txt file from which I can grab specific titles via a perl one-liner:
$ perl -ne 'print if (m{^("?)[1-9]*\.})' tables
1. ${title1}
2. ${title2}
"3. ${title3}",,,
4. one more title
5. nuther title
6. and so on...,,
...
25. last title
I can't seem to get the same titles to appear using python:
$ python -V
Python 3.5.2
$ python
Python 3.5.2 (default, Jul 5 2016, 12:43:10)
[GCC 5.4.0 20160609] on linux
Type "help", "copyright", "credits" or "license" for more information.
import os
import re
with open('tables','rt') as f:
data = f.read()
printing data results in the output I would expect..
Trying to compile a regex and display the results does not show the same
results I get from perl.
regex = r'^("?)[1-9]*\.'
re.search(regex, data)
p = re.compile(r'^("?)[1-9]*\.')
p
re.compile('^("?)[1-9]*\\.')
p.findall(data)
I've tried any number of options shown on the net all with the same result.
Can someone point out what I'm messing up?
I think the difference is the anchor ^. In perl, you apply the regex to
each line, whereas in Python you apply it to the whole file. You would
either need to switch the re to multiline mode
https://docs.python.org/2/library/re.html#re.MULTILINE
or do it in a loop, the same way that perl does it implicitly:
for line in f:
print(re.findall(line).group(0))
(untested)
Christian
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