GP wrote:
The error and your second snippet aren't compatible, so I assume the
exception is raised by
> for k in range(0,len(shelf)):
> q1=ListDictItem[k]
> q2 = ListDictItem.pop(k) #deletes the items that are packed.
> Error message:Traceback (most recent call last):
> File "C:\Project\Python\ReadExcel-xlrd.py", line 201, in <module>
> q1=ListDictItem[k]
> IndexError: list index out of range.
Take a moment to understand what happens if you iterate over the loop index
like above:
items = ["foo", "bar", "baz"]
for k in range(len(items)):
item = items[k]
print(item)
items.pop(k)
You start with k=0, item is set to items[0], i. e. "foo", that is printed
and then items.pop(0) removes "foo" from the list which now looks like
items = ["bar", "baz"]
Now k=1, item is set to items[1], ie. "baz" ("bar" is never processed),
"baz" is printed and then items.pop(1) removes "baz" and the list becomes
items = ["bar"]
Now k=2, so when you access items[2] from a list with only one item you get
the IndexError. To make similar code work you need a while loop:
while items:
item = items.pop(0)
print(item)
However, when you really want to remove all items you instead assign a new
empty list
for item in items:
print(item)
items = []
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