On Thu, Aug 18, 2016 at 9:13 AM, Dennis Lee Bieber <wlfr...@ix.netcom.com> wrote: > On Wed, 17 Aug 2016 18:52:22 +0100, MRAB <pyt...@mrabarnett.plus.com> > declaimed the following: > > >> >>If "p" points to a struct (record), then "*p" is that struct, and if >>that struct has a member (field) "m", then that member can be accessed >>by "(*p)->m" (the parens are necessary because of the operator >>precedence). This can be abbreviated to "p->m". >> > > I'd have to test, but I think > > (*p).m is what is equivalent to p->m > > IE; dereference the pointer, and then access the member of the struct
Folks, read the whole thread before posting :) This was a simple error that has already been mentioned earlier in the thread. (Sorry to single you out, Dennis - I'm not trying to hate on you personally here.) ChrisA -- https://mail.python.org/mailman/listinfo/python-list
