OK - I actually got something working last night with a list that is then
converted into a dictionary (dealing with small sets of data - < 200 files per
run). However, I like the sorted list option - I didn't realize that was even
an option within the definition and wasn't quite sure how to get there. I
realized I could use os.path.splitext and cast that to an int, but was having
trouble with the sort.
My files only have a single "." in them so this will work well for me.
(from Tom's code)
[name for dec,name in
sorted((int(os.path.splitext(nm)[1][1:]),nm) for nm in namelist)]
I'll give that a try - it would eliminate the dictionary part of my code and be
a little more efficient.
Thanks to all for the quick responses.
-Pete
Peter A. Schott <[EMAIL PROTECTED]> wrote:
> Trying to operate on a list of files similar to this:
>
> test.1
> test.2
> test.3
> test.4
> test.10
> test.15
> test.20
>
> etc.
>
> I want to sort them in numeric order instead of string order. I'm starting
> with
> this code:
>
> import os
>
> for filename in [filename for filename in os.listdir(os.getcwd())]:
> print filename
> #Write to file, but with filenames sorted by extension
>
>
> Desired result is a file containing something like:
> C:\MyFolder\test.1,test.001
> C:\MyFolder\test.2,test.002
> C:\MyFolder\test.3,test.003
> C:\MyFolder\test.4,test.004
> C:\MyFolder\test.10,test.010
> C:\MyFolder\test.15,test.015
> C:\MyFolder\test.20,test.020
>
> I need to order by that extension for the file output.
>
> I know I've got to be missing something pretty simple, but am not sure what.
> Does anyone have any ideas on what I'm missing?
>
> Thanks.
>
> -Pete Schott
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