On Thursday, July 14, 2016 at 10:39:35 AM UTC-7, Carter Temm wrote: > Hi all. > I've been looking at this for a bit, and can't seem to come to a possible > conclusion on what could be happening to get an error. Anyway, here is the > code, then I'll explain. > > http://pastebin.com/raw/YPiTfWbG > > the issue comes when using argv. But when I change > > TIME = argv > > to > > TIME = 2 > > It does exactly what I intended, no issues. What's wrong? Thanks for any help. > > > > Also, The error I get when trying to run is: Traceback (most recent call > last): File "sound_recorder.py", line 21, in <module> for i in range(0, > int(RATE / CHUNK * TIME)): OverflowError: range() result has too many items‬
argv is a list containing the name (or path depending on OS) of the script and all the command line parameters passed to it. I suspect that the problem is that the contents of argv will be strings, but you need TIME to be an integer. Even if you use "python myScript.py 5", argv[1] will be a string because Python doesn't know if "5" is actually supposed to be an integer, or if your script might be expecting a file name, and you have a file named "5". An OverflowError when using range(..) usually means your range is too big. I'm assuming you're using Python 2.x. Try printing int(RATE / CHUNK * TIME) to see if the value is what you're expecting. Also consider using xrange(..). It doesn't require the entire list to be stored in memory. -- https://mail.python.org/mailman/listinfo/python-list
