Ray wrote:
> Hello,
>
> I've been learning Python in my sparetime. I'm a Java/C++ programmer by
> trade. So I've been reading about Python OO, and I have a few questions
> that I haven't found the answers for :)
>
> 1. Where are the access specifiers? (public, protected, private)
object.name => public
object._name => protected
object.__name => private
> 2. How does Python know whether a class is new style or old style?
> E.g.:
>
> class A:
> pass
This is an old-style class.
> How does it know whether the class is new style or old style? Or this
> decision only happens when I've added something that belongs to new
> style? How do I tell Python which one I want to use?
class B(object): # or any subclass of object
pass
> 3. In Java we have static (class) method and instance members. But this
> difference seems to blur in Python. I mean, when you bind a member
> variable in Python, is it static, or instance?
Depends if you bind it to the class or to the instance !-)
> It seems that everything
> is static (in the Java sense) in Python. Am I correct?
No.
class Foo(object):
bar = 42 # this is a class variable
# __init__ is the equivalent of Java constructors
def __init__(self, baaz):
self.baaz = baaz # this is an instance variable
# this is a class method
# (the first argument is the class object, not the instance)
@classmethod
def bak(cls, frooz):
cls.bar = min(cls.bar, frooz) + 1138
# default is instance method
def zoor(self):
print "%s %d" % (self.baaz, Foo.bar)
> Thanks in advance,
HTH
--
bruno desthuilliers
ruby -e "print '[EMAIL PROTECTED]'.split('@').collect{|p|
p.split('.').collect{|w| w.reverse}.join('.')}.join('@')"
python -c "print '@'.join(['.'.join([w[::-1] for w in p.split('.')]) for
p in '[EMAIL PROTECTED]'.split('@')])"
--
http://mail.python.org/mailman/listinfo/python-list
