Tom Deco wrote:
> Hi,
>
> I'm trying to use a regular expression to match a string containing a #
> (basically i'm looking for #include ...)
>
> I don't seem to manage to write a regular expression that matches this.
>
> My (probably to naive) approach is: p = re.compile(r'\b#include\b)
> I also tried p = re.compile(r'\b\#include\b) in a futile attempt to use
> a backslash as escape character before the #
> None of the above return a match for a string like "#include <stdio>".
>
> I know a # is used for comments, hence my attempt to escape it...
>
> Any suggestion on how to get a regular expression to find a #?
>
> Thanks
>
You definitely shouldn't have the first \b -- match() works only at the
beginning of the target string, so it is impossible for there to be a
word boundary just before the "#".
You probably shouldn't have the second \b.
You probably should read section A12 of K&R2.
You probably should be using a parser, but if you persist in using
regular expressions:
(a) read the manual.
(b) try something like this:
>>> pat1 = re.compile(r'\s*#\s*include\s*<\s*([^>\s]+)\s*>\s*$')
>>> pat1.match(" # include < fubar.h > ").group(1)
'fubar.h'
N.B. this is based the assumption that sane programmers don't have
whitespace embedded in the names of source files ;-)
HTH,
John
--
http://mail.python.org/mailman/listinfo/python-list
