Mehrzad Irani wrote:
> Hi All,
>
> Consider the situation
> [cti@iranim-rhel python_cti]$ cat a.py
> def a(a = 1, b = 2, c = 3, *d, **e):
> print(a, b, c)
> print(d)
> print(e)
>
> r = {'e': 7, 'f': 8, 'g': 9}
>
>
> a(**r)
> a(3, **r)
>
> r1 = (4,5,6)
>
> a(3,2,1,*r1, **r)
> a(*r1, **r)
>
> r1 = (4,5,6,7)
> a(*r1, **r)
>
> [cti@iranim-rhel python_cti]$
>
> The output for this program is as follows:
> [cti@iranim-rhel python_cti]$ python a.py
> (1, 2, 3)
> ()
> {'e': 7, 'g': 9, 'f': 8}
> ------------------
> (3, 2, 3)
> ()
> {'e': 7, 'g': 9, 'f': 8}
> ------------------
> (3, 2, 1)
> (4, 5, 6)
> {'e': 7, 'g': 9, 'f': 8}
> ------------------
> (4, 5, 6)
> ()
> {'e': 7, 'g': 9, 'f': 8}
> ------------------
> (4, 5, 6)
> (7,)
> {'e': 7, 'g': 9, 'f': 8}
>
> This program shows, that for d to get assigned, I would need to first
> assign a, b, c even though their default parameters have been set.
>
> Also, if I would like to unpack a, b, c using e; I would get a multiple
> assignment TypeError.
>
> Therefore, my question is - is there a way to assign d, without going
> through the assignments of a, b, c again, since they have already been
> assigned defaults? (I think I am missing something simple here)
>
> Thanks in advance.
Python 3 allows
$ cat b.py
def a(*d, a=1, b=2, c=3, **e):
print(a, b, c)
print(d)
print(e)
r = {'e': 7, 'f': 8, 'g': 9}
a(**r)
a(3, **r)
r1 = (4,5,6)
a(3,2,1,*r1, **r)
a(*r1, **r)
r1 = (4,5,6,7)
a(*r1, **r)
$ python3 b.py
1 2 3
()
{'e': 7, 'f': 8, 'g': 9}
1 2 3
(3,)
{'e': 7, 'f': 8, 'g': 9}
1 2 3
(3, 2, 1, 4, 5, 6)
{'e': 7, 'f': 8, 'g': 9}
1 2 3
(4, 5, 6)
{'e': 7, 'f': 8, 'g': 9}
1 2 3
(4, 5, 6, 7)
{'e': 7, 'f': 8, 'g': 9}
Perhaps that is more to your liking? I find the output as unreadable as of
your a.py, so I won't bother to check...
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