What have code you tried? What error message are you receiving?
On Fri, May 13, 2016, 5:54 PM David Shi <davidg...@yahoo.co.uk> wrote:
> Hello, Michael,
>
> How to convert a float type column into an integer or label or string type?
>
>
> On Friday, 13 May 2016, 22:02, Michael Selik <michael.se...@gmail.com>
> wrote:
>
>
> To clarify that you're specifying the index as a label, use df.iloc
>
> >>> df = pd.DataFrame({'X': range(4)}, index=list('abcd'))
> >>> df
> X
> a 0
> b 1
> c 2
> d 3
> >>> df.loc['a']
> X 0
> Name: a, dtype: int64
> >>> df.iloc[0]
> X 0
> Name: a, dtype: int64
>
> On Fri, May 13, 2016 at 4:54 PM David Shi <davidg...@yahoo.co.uk> wrote:
>
> Dear Michael,
>
> To avoid complication, I only groupby using one column.
>
> It is OK now. But, how to refer to new row index? How do I use floating
> index?
>
> Float64Index([ 1.0, 4.0, 5.0, 6.0, 8.0, 9.0, 10.0, 11.0, 12.0, 13.0,
> 16.0,
> 17.0, 18.0, 19.0, 20.0, 21.0, 22.0, 23.0, 24.0, 25.0, 26.0,
> 27.0,
> 28.0, 29.0, 30.0, 31.0, 32.0, 33.0, 34.0, 35.0, 36.0, 37.0,
> 38.0,
> 39.0, 40.0, 41.0, 42.0, 44.0, 45.0, 46.0, 47.0, 48.0, 49.0,
> 50.0,
> 51.0, 53.0, 54.0, 55.0, 56.0],
> dtype='float64', name=u'StateFIPS')
>
>
> Regards.
>
>
> David
>
>
>
> On Friday, 13 May 2016, 21:43, Michael Selik <michael.se...@gmail.com>
> wrote:
>
>
> Here's an example.
>
> >>> import pandas as pd
> >>> df = pd.DataFrame({'group': list('AB') * 2, 'data': range(4)},
> index=list('wxyz'))
> >>> df
> data group
> w 0 A
> x 1 B
> y 2 A
> z 3 B
> >>> df = df.reset_index()
> >>> df
> index data group
> 0 w 0 A
> 1 x 1 B
> 2 y 2 A
> 3 z 3 B
> >>> df.groupby('group').max()
> index data
> group
> A y 2
> B z 3
>
> If that doesn't help, you'll need to explain what you're trying to
> accomplish in detail -- what variables you started with, what
> transformations you want to do, and what variables you hope to have when
> finished.
>
> On Fri, May 13, 2016 at 4:36 PM David Shi <davidg...@yahoo.co.uk> wrote:
>
> Hello, Michael,
>
> I changed groupby with one column.
>
> The index is different.
>
> Index([ u'AL', u'AR', u'AZ', u'CA', u'CO', u'CT', u'DC',
> u'DE', u'FL', u'GA', u'IA', u'ID', u'IL', u'IN',
> u'KS', u'KY', u'LA', u'MA', u'MD', u'ME', u'MI',
> u'MN', u'MO', u'MS', u'MT', u'NC', u'ND', u'NE',
> u'NH', u'NJ', u'NM', u'NV', u'NY', u'OH', u'OK',
> u'OR', u'PA', u'RI', u'SC', u'SD', u'State', u'TN',
> u'TX', u'UT', u'VA', u'VT', u'WA', u'WI', u'WV',
> u'WY'],
> dtype='object', name=0)
>
>
> How to use this index?
>
>
> Regards.
>
>
> David
>
>
>
> On Friday, 13 May 2016, 21:19, David Shi <davidg...@yahoo.co.uk> wrote:
>
>
> Hello, Michael,
>
> I typed in df.index
>
> I got the following
>
> MultiIndex(levels=[[1.0, 4.0, 5.0, 6.0, 8.0, 9.0, 10.0, 11.0, 12.0, 13.0,
> 16.0, 17.0, 18.0, 19.0, 20.0, 21.0, 22.0, 23.0, 24.0, 25.0, 26.0, 27.0, 28.0,
> 29.0, 30.0, 31.0, 32.0, 33.0, 34.0, 35.0, 36.0, 37.0, 38.0, 39.0, 40.0, 41.0,
> 42.0, 44.0, 45.0, 46.0, 47.0, 48.0, 49.0, 50.0, 51.0, 53.0, 54.0, 55.0,
> 56.0], [u'AL', u'AR', u'AZ', u'CA', u'CO', u'CT', u'DC', u'DE', u'FL', u'GA',
> u'IA', u'ID', u'IL', u'IN', u'KS', u'KY', u'LA', u'MA', u'MD', u'ME', u'MI',
> u'MN', u'MO', u'MS', u'MT', u'NC', u'ND', u'NE', u'NH', u'NJ', u'NM', u'NV',
> u'NY', u'OH', u'OK', u'OR', u'PA', u'RI', u'SC', u'SD', u'State', u'TN',
> u'TX', u'UT', u'VA', u'VT', u'WA', u'WI', u'WV', u'WY']],
> labels=[[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16,
> 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35,
> 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48], [0, 2, 1, 3, 4, 5, 7, 6,
> 8, 9, 11, 12, 13, 10, 14, 15, 16, 19, 18, 17, 20, 21, 23, 22, 24, 27, 31, 28,
> 29, 30, 32, 25, 26, 33, 34, 35, 36, 37, 38, 39, 41, 42, 43, 45, 44, 46, 48,
> 47, 49]],
> names=[u'StateFIPS', 0])
>
> Regards.
>
>
> David
>
>
>
> On Friday, 13 May 2016, 21:11, David Shi <davidg...@yahoo.co.uk> wrote:
>
>
> Dear Michael,
>
> I have done a number of operation in between.
>
> Providing that information does not help you
>
> How to reset index after grouping and various operations is of interest.
>
> How to type in a command to find out its current dataframe?
>
> Regards.
>
> David
>
>
> On Friday, 13 May 2016, 20:58, Michael Selik <michael.se...@gmail.com>
> wrote:
>
>
> Just in case I misunderstood, why don't you make a little example of
> before and after the grouping? This mailing list does not accept
> attachments, so you'll have to make do with pasting a few rows of
> comma-separated or tab-separated values.
>
> On Fri, May 13, 2016 at 3:56 PM Michael Selik <michael.se...@gmail.com>
> wrote:
>
> In order to preserve your index after the aggregation, you need to make
> sure it is considered a data column (via reset_index) and then choose how
> your aggregation will operate on that column.
>
> On Fri, May 13, 2016 at 3:29 PM David Shi <davidg...@yahoo.co.uk> wrote:
>
> Hello, Michael,
>
> Why reset_index before grouping?
>
> Regards.
>
> David
>
>
> On Friday, 13 May 2016, 17:57, Michael Selik <michael.se...@gmail.com>
> wrote:
>
>
>
>
> On Fri, May 13, 2016 at 12:27 PM David Shi via Python-list <
> python-list@python.org> wrote:
>
> I lost my indexes after grouping in Pandas.
> I managed to rest_index and got back the index column.
> But How can I get back a index row?
>
>
> Was the grouping an aggregation? If so, the original indexes are
> meaningless. What you could do is reset_index before the grouping and when
> you aggregate decide how to handle the formerly-known-as-index column (min,
> max, mean, ?).
>
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