If you can't change A to use something like "type(self)(...)" to create its
return value, you could use the dark side and swap res's __class__:
res.__class__ = B
Or:
res.__class__ = type(self)
Do note that B.__init__ will not be run when you do this, so it is up to
you to execute any additional initialization B might require.
Alternatively if it makes sense for you you can call B's methods on an A
object like so:
B.b_method(a_object, ...)
On Mon, 9 May 2016 at 06:26 Paulo da Silva <p_s_d_a_s_i_l_v_a...@netcabo.pt>
wrote:
> Hi!
>
> Suppose I have a class A whose implementation I don't know about.
> That class A has a method f that returns a A object.
>
> class A:
> ...
> def f(self, <...>):
> ...
>
> Now I want to write B derived from A with method f1. I want f1 to return
> a B object:
>
> class B(A):
> ...
> def f1(self, <...>):
> ...
> res=f(<...>)
>
> How do I return res as a B object?
>
> Thanks.
> --
> https://mail.python.org/mailman/listinfo/python-list
>
--
Yann Kaiser
kaiser.y...@gmail.com
yann.kai...@efrei.net
+33 6 51 64 01 89
https://github.com/epsy
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