On Sat, Apr 30, 2016, at 09:48 AM, Christopher Reimer wrote:
> On 4/29/2016 11:43 PM, Stephen Hansen wrote:
> > The official documentation is accurate.
>
> That may be true on a technical level. But the identically worded text
> in the documentation implies otherwise.
That's the thing -- no it doesn't. The documentation is very specific:
if all cased characters in the string are lowercase, and there's at
least one cased character.
It only seems to because you're packing a loop and test on substrings
into an operation.
list(filter((lambda x: not x.islower()), string))
Let's unpack that. This is basically what you're doing:
result = []
for ch in string:
if not ch.islower():
result.append(ch)
You're thinking of the whole "string", but you're operating on
single-character substrings, and when " ".islower() is run, its false.
Because the two-pronged test, a) if all cased characters are lowercase
and b) there is at least one cased character. b) is failing. Ergo,
you're getting the underscores.
--
Stephen Hansen
m e @ i x o k a i . i o
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