On Wed, Apr 6, 2016 at 1:22 PM, Marko Rauhamaa <ma...@pacujo.net> wrote: > However, BartC's No-Buzzword Python doesn't have classes... If he > allowed for types.SimpleNamespace, we could have: > > ======================================================================== > import types > > def While(predicate): > def __iter__(): > return thingy > def __next__(): > if thingy._exited or not predicate(): > thingy._exited = True > raise StopIteration > thingy = types.SimpleNamespace( > _exited=False, __iter__=__iter__, __next__=__next__) > return thingy > ======================================================================== > > However, that results in: > > TypeError: 'types.SimpleNamespace' object is not iterable > > Where's my bug? Or is CPython buggy? Or is it the documentation: > > The iterator objects themselves are required to support the > following two methods, which together form the iterator protocol: > > iterator.__iter__() > > [...] > > iterator.__next__() > > <URL: https://docs.python.org/3/library/stdtypes.html#typeiter> > > Why is a SimpleNamespace object not an iterator even though it provides > __iter__ and __next__?
Because Python expects those methods to be defined in the class dict, not the instance dict. In a world with only SimpleNamespace and no classes, I think we could reasonably expect that to work (assuming that the iterator protocol is even still a thing in that world). -- https://mail.python.org/mailman/listinfo/python-list
