Chris Angelico writes:
> On Fri, Mar 11, 2016 at 5:33 AM, Neal Becker wrote:
>> Is there a way to ensure resource cleanup with a construct such as:
>>
>> x = load (open ('my file', 'rb))
>>
>> Is there a way to ensure this file gets closed?
>
> Yep!
>
> def read_file(fn, *a, **kw):
> with open(fn, *a, **kw) as f:
> return f.read()
>
> Now you can ensure resource cleanup, because the entire file has been
> read in before the function returns. As long as your load() function
> is okay with reading from a string, this is effective.
Make the string look like a file object to the load function:
import io
def clopen(fn, mode = 'r', encoding = None):
with open(fn, mode = mode, encoding = encoding) as f:
ModeIO = io.BytesIO if 'b' in mode else io.StringIO
return ModeIO(f.read())
x = load(clopen('my-file', 'rb'))
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