Le 07/03/2016 09:24, Faling Dutchman a écrit :
Hey folks,
I am just starting off in python, but have good knowledge of both Java and C#.
Now is the problem that I need to have multiple instances of one dictionary,
that is not a problem if you know how many, but now, it is an unknown amount.
Some background info:
I am making a library for an API. This library must be easy to use for the
people who are going to use it. So I am making the models for the data, the
connections and so on, so they just have to fill in the gaps. In C# and Java I
did it with objects, but they do not work alike in python, or at least that is
what I have found.
If I do this:
class Item:
def __init__(self, id, productId, quantity, pageCount, files, option,
metadata):
self.id = id
self.productId = productId
self.quantity = quantity
self.pageCount = pageCount
self.files = files
self.option = option
self.metadata = metadata
itm = Item(1,None,1,1,'asdf',{'asdf': 3, 'ads': 55},None)
print(itm)
it prints: <__main__.Item object at 0x02EBF3B0>
So that is not usefull to me. There can be an infinite amount of objects of
Item, and it needs to be easy accessable, just like
for i in items
print(i)
and it has to show all the parameters of the class Item and not say "ive got an
object at this memory address, have a nice day"
I hope my question is clear.
The classes have a dict
Python 3.2.3 (default, Jun 18 2015, 21:46:42)
[GCC 4.6.3] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> class Item:
... def __init__(self, id, productId, quantity, pageCount, files,
option, metadata):
... self.id = id
... self.productId = productId
... self.quantity = quantity
... self.pageCount = pageCount
... self.files = files
... self.option = option
... self.metadata = metadata
...
>>> i = Item(1,None,1,1,'asdf',{'asdf': 3, 'ads': 55},None)
>>> i.__dict__
{'files': 'asdf', 'option': {'ads': 55, 'asdf': 3}, 'pageCount': 1,
'metadata': None, 'productId': None, 'id': 1, 'quantity': 1}
>>>
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