Op 05-03-16 om 16:18 schreef Chris Angelico:
> On Sun, Mar 6, 2016 at 2:05 AM, Antoon Pardon
> <antoon.par...@rece.vub.ac.be> wrote:
>> Using python 3.4/3.5
>>
>> Suppose I have the following class:
>>
>> class Tryout:
>>
>> @extern
>> def method(self, ...)
>>
>> Now how can I have access to the Tryout class in
>> the extern function when it is called with method
>> as argument
>>
>> def extern(f):
>> the_class = ????
>>
>> f.__class doesn't work, if I write the following
>>
>> def extern(f)
>> print(f.__class__)
>>
>> the result is: <class 'function'>, so that doesn't work.
>> Looking around I didn't find an other obvious candidate
>> to try. Anybody an idea?
>
> At the time when the function decorator is run, there isn't any class.
> You could just as effectively create your function outside the class
> and then inject it (Tryout.method = method).
>
> What is it you're trying to do? Would it be a problem to have a class
> decorator instead/as well?
>
> ChrisA
>
The idea is that some of these methods will be externally available
and others are not. So that I get an external string and can do
something of the following:
tryout = Tryout()
st = read_next_cmd()
if st in tryout.allowed:
getattr(tryout, st)()
else:
raise ValueError("%s: unallowed cmd string" % st)
And the way I wanted to populate Tryout.allowed as a class attribute
would have been with the decorator extern, which would just have put
the name of the method in the Tryout.allowed set and then return the function.
--
https://mail.python.org/mailman/listinfo/python-list
