On Wednesday, 13 January 2016 13:23:04 UTC, Alan Robinson wrote:
> On Wednesday, 13 January 2016 13:06:11 UTC, Peter Otten wrote:
> > Alan Robinson wrote:
> >
> > > On Wednesday, 13 January 2016 12:32:51 UTC, Chris Angelico wrote:
> > >> On Wed, Jan 13, 2016 at 11:23 PM, Alan Robinson
> > >> <arobin...@lordlawson.org.uk> wrote:
> > >> > def menu():
> > >> > option = int(input("Please select an option: \n 1: Set Generation 0
> > >> > Values \n 2: View Generation 0 Values \n 3: Run Model \n 4: Print
> > >> > values"))
> > >> >
> > >> > if option == 1:
> > >> > juveniles,adults,seniles = setGen()
> > >> > elif option == 2:
> > >> > displayGen()
> > >> > elif option == 3:
> > >> > runModel(juveniles,adults,seniles)
> > >> > elif option == 4:
> > >> > print(juveniles,adults,seniles)
> > >> > menu()
> > >> >
> > >>
> > >> This is a classic use of recursion instead of iteration. When you call
> > >> menu() again, you're creating a completely new 'slot' for the new
> > >> function; it has its own set of names. Assigning to names in one call
> > >> of menu() has no effect on any other call.
> > >>
> > >> Instead, look into the way a while loop works. You'll find that your
> > >> code is simpler and clearer, plus your variables will stay set.
> > >>
> > >> ChrisA
> > > thanks I need the menu to run again not sure how to do that though
> >
> > def menu():
> > option = 1 # make sure setGen is invoked on first iteration
> > while option: # choosing 0 ends the while loop
> > if option == 1:
> > juveniles, adults, seniles = setGen()
> > elif option == 2:
> > ...
> > option = int(input(...)) # choose option for the next iteration
>
> that's really helpful I understand what's happening now I just need to work
> out how to do this loop as I am new it looks difficult to do here goes not
> too sure what you mean by make sure setGen is invoked on the first iteration?
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