On 13/12/2015 17:26, Ganesh Pal wrote:
Iam on linux and python 2.7 . I have a bunch of functions which I
have run sequentially .
I have put them in a list and Iam calling the functions in the list as
shown below , this works fine for me , please share your
opinion/views on the same
Sample code :
def print1():
print "one"
def print2():
print "two"
def print3():
print "three"
print_test = [print1(),print2(),print3()] //calling the function
for test in range(len(print_test)):
try:
print_test[test]
except AssertionError as exc:
> I have put them in a list and Iam calling the functions in the list as
> shown below , this works fine for me , please share your
That's not quite what the code does, which is to call the three
functions and put their results into the list (3 Nones I think).
Then you evaluate each element of the list (a None each time).
I had to modify it to the following, which sets up a list of the three
functions, then calls them in turn using the loop. I don't know what the
'except' part was supposed to do:
def print1():
print "one"
def print2():
print "two"
def print3():
print "three"
print_test = [print1,print2,print3] #NOT calling the function
for test in range(len(print_test)):
try:
print_test[test]() #calling the function
except AssertionError:
pass
The output of the two programs would have been the same I think.
--
Bartc
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