Felix Collins wrote:
> Hi All,
> does anyone know any cleaver tricks to sort a list of outline numbers.
>
> An outline number is a number of the form... 1.2.3
>
> they should be sorted in the following way...
>
> 1
> 1.1
> 1.2
> 1.12
>
> python's alpha sort (by design) sorts them...
>
> 1
> 1.1
> 1.12
> 1.2
>
> That's no good for me.
> I'm planning on splitting the strings into multiple lists of ints and
> doing numerical sorts.
>
> Thanks for any clever ideas that might make it easier.
Use the "key" keyword argument to list.sort().
In [1]: outline = ['1.12', '1.1', '1', '1.2']
In [2]: outline.sort(key=lambda x: map(int, x.split('.')))
In [3]: outline
Out[3]: ['1', '1.1', '1.2', '1.12']
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