I have a python class that wraps a boost.python object. I am using a
boost.python library function that requires the raw boost.python object. I want
to be able to pass the python object to the boost api function.
Is there a hook available on the python side that instructs boost to perform a
conversion?
Hypothetically, it would be something like this:
class EggWrapper(object):
def __init__(self, egg):
object.__setattr__(self, '_egg', egg)
def __getattribute__(self, name):
egg = object.__getattribute__(self, '_egg')
if name=='_egg':
return egg
if name in EggWrapper.__dict__:
return object.__getattribute__(self, name)
return getattr(egg, name)
def __setattr__(self, name, value):
egg = object.__getattribute__(self, '_egg')
setattr(egg, name, value)
def magic_boost_conversion_unicorn_hook(self):
'this is automatically called by boost to convert arguments'
egg = object.__getattribute__(self, '_egg')
return egg
import myboostlib
egg = EggWrapper(myboostlib.getEgg())
myboostlib.spam(egg)
Where the signature for spam is: spam(class boost::python::api::object)
And myboostlib.getEgg() returns a boost::python::api::object
- I do not have the ability to modify the library or any C/C++ code, the
solution must be entirely on the python side.
- I can't change the calling convention. The wrapped object must be used (i.e.
I can't just say myboostlib.spam(egg._egg), though that is the desired result).
So the solution should be incorporated into the EggWrapper class.
- I'm only interested in solutions that reflect expert knowledge of
Boost.Python, since I believe I have already considered all the trivial
solutions.
So my question is, does magic_boost_conversion_unicorn_hook() exist, and if so,
how is it spelled?
Thanks,
~ Ken
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