I need to add: you need to look up the stack to see if you have been
called by __main__ and if __main__.__file__ is missing.
Implementation: I would write decorator for your func.
Best,
Sven
PS: did I say it would probably be a bad idea? If not, it would probably
be a bad idea.
PPS: what is the reason for this special behavior?
On 10.09.2015 20:03, Sven R. Kunze wrote:
http://stackoverflow.com/questions/2356399/tell-if-python-is-in-interactive-mode
On 10.09.2015 19:54, Steven D'Aprano wrote:
I have a function which is intended for use at the interactive
interpreter,
but may sometimes be used non-interactively. I wish to change it's
output
depending on the context of how it is being called.
If the function is being called as if it were a procedure or command,
that
is the return result is just ignored, I want to return one thing. But
if it
is being called where the return result goes somewhere, I want to return
something else. Most importantly, I don't want to pass a flag to the
function myself, I want the function to know its own context.
I don't mind if it is CPython only, or if it is a bit expensive.
E.g.
def func():
do_stuff()
if procedure: # FIXME what goes here???
return "Awesome"
else:
return 999
Now I can do this:
x = func()
assert x == 999
L = [1, 2, func(), 4]
assert L[2] == 999
func()
# interactive interpreter prints "Awesome"
Is such a thing possible, and if so, how would I do it?
If I did this thing, would people follow me down the street booing and
jeering and throwing things at me?
Probably. ;)
But it it solve a problem, why not.
Best,
Sven
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