On Fri, Aug 7, 2015 at 10:34 AM, <sohcahto...@gmail.com> wrote: > Despite my "except KeyboardInterrupt", the KeyboardInterrupt forced by the > thread.interrupt_main() in the worker thread isn't being caught. > > Other things worth noting is that the exception takes about 3 seconds after > the call to thread.interrupt_main(). It appears to not actually happen until > the sock.accept() times out. If the call to sock.settimeout(5) is removed, > the KeyboardInterrupt never appears and flow is still blocked on the > sock.accept(). > > My Python version is 2.7.3. I know its out of date, but I don't really have > a choice.
As far as I know, the only effect of thread.interrupt_main() is to set a flag saying "Hey main thread, next time you go checking for these things, there's a KeyboardInterrupt waiting for you". It doesn't actually send an OS-level signal, which means it cannot interrupt a blocking call. So you have a few choices: 1) Shorten the timeout on sock.accept() to an (if you'll excuse the pun) acceptable delay, and then simply check a flag. Something like this: interrupt = False while not interrupt: try: connection, _ = sock.accept() except socket.timeout: # On timeout, check flag and keep sleeping pass If you wish to also have an actual timeout, you could monitor that separately. 2) Instead of blocking on sock.accept directly, have another event which the other thread can raise, which will wake the main thread. You could use select.select() for this. 3) Bury the details of select.select() away behind a nice framework like asyncio, merge your two threads, and run everything through a back-end event loop. 4) Use separate processes, and signal the interrupt using an OS-level notification (on Unix systems, SIGINT; on Windows, there's an equivalent called BreakSignal or something). This will break out of the underlying system call that handles accept(). thread.interrupt_main() is similar to just setting a global that you periodically check, except that the periodic check is handled for you by the system. That's really all. ChrisA -- https://mail.python.org/mailman/listinfo/python-list