fl writes: > aa=[1, 2, 3].remove(2) > > I don't know where the result goes. Could you help me on the question?
That method modifies the list and returns None (or raises an exception). Get a hold on the list first: aa=[1, 2, 3] *Then* call the method. Just call the method, do not try to store the value (which will be None) anywhere: aa.remove(2) *Now* you can see that the list has changed. Try it. By the way, it's no use to try [1, 2, 3].remove(2). That will only modify and throw away a different list that just happens to have the same contents initially. Try these two: aa=[1, 2, 3] bb=[1, 2, 3] # a different list! aa=[1, 2, 3] bb=aa # the same list! In both cases, try removing 2 from aa and then watch what happens to aa and what happens to bb. -- https://mail.python.org/mailman/listinfo/python-list
