On Friday, June 12, 2015 at 3:12:26 PM UTC-7, Thomas 'PointedEars' Lahn wrote: > Ian Kelly wrote: > > > [...] Thomas 'PointedEars' Lahn [...] wrote: > >> Ian Kelly wrote: > >>> The probability of 123456789 and 111111111 are equal. The probability > >>> of a sequence containing all nine numbers and a sequence containing > >>> only 1s are *not* equal.d > >> There is a contradiction in that statement. Can you find it? > > > > Yes. I phrased my statement as if I were addressing a rational > > individual, in clear contradiction of the current evidence. > > > > Seriously, if you reject even the statement I made above, in spite of > > all the arguments that have been advanced in this thread, in spite of > > the fact that this is very easy to demonstrate empirically, then I > > don't think there's any fertile ground for discussion here. > > /Ad hominem/ when out of arguments. How typical. > > Do you deny that "123456789" *is* "a sequence containing all nine numbers" > (digits, really), and that "111111111" *is* "a sequence containing only 1s"? > > Do you deny that therefore your second sentence contradicts the first one? > > -- > PointedEars > > Twitter: @PointedEars2 > Please do not cc me. / Bitte keine Kopien per E-Mail.
I'm struggling to see the contradiction here. Yes, 123456789 is a sequence containing all nine numbers. And as someone else said, 123456798 is also a sequence containing all numbers. 987654321 contains all numbers. There are 9*8*7*6*5*4*3*2*1 (Usually expressed as "9!", and equal to 362,880) distinct ways to order nine numbers. However, there is only ONE way to order a series of all 1s. There's no contradiction here. -- https://mail.python.org/mailman/listinfo/python-list
