In article <mailman.118.1431989304.17265.python-l...@python.org>,
Cameron Simpson <c...@zip.com.au> wrote:
>On 16May2015 12:20, C.D. Reimer <ch...@cdreimer.com> wrote:
>>title = slug.replace('-',' ').title()
>>This line also works if I switched the dot operators around.
>>title = slug.title().replace('-',' ')
>>
>>I'm reading the first example as character replacement first and title
>>capitalization second, and the second example as title capitalization
>>first and character replacement second.
>>
>>Does python perform the dot operators from left to right or according
>>to a rule of order (i.e., multiplication/division before add/subtract)?
>
>I've been thinking about the mindset that asks this question.
>
>I think the reason you needed to ask it was that you were thinking in terms of
>each .foo() operation acting on the original "slug". They do not.
>
>"slug" is an expression returning, of course, itself.
>
>"slug.title()" is an expression returning a new string which is a titlecased
>version of "slug".
Why is "slug.title" a valid decomposition of the total string>
(Or is it?)
What is the ()-brackets doing? Does it force the execution of title,
which gives something to be dotted onto slug etc. See below.
>
>"slug.title().replace(...)" is an expression which _operates on_ that new
>string, _not_ on "slug".
>
>In particular, each .foo() need not return a string - it might return anything,
>and the following .bah() will work on that anything.
I interpreted the question as about the associative of the
dot operator.
title = slug.title().replace('-',' ')
Does that mean
title = slug.( title().replace('-',' ') )
or
title = ( slug.( title()) .replace('-',' ')
or is it even <slot>.<slot>.<slot> a ternary operator with
special syntax like we have in
<slot> <= <slot> <= <slot>
lately.
It seems to me that you presuppose the answer.
>
>Cheers,
>Cameron Simpson <c...@zip.com.au>
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