On 05/26/2015 05:43 PM, richard_riehle wrote:
I realized that I mentioned earlier that I found a solution to my original
question, but that I never posted an example of the solution. So, here is a
simplified example for anyone who is interested.
def fArray(fselect, fparm = 1):
def A1(p = fparm):
if p == 1:
print("printing A1[1]")
else:
print("printing A1[other]")
def A2(p = fparm):
if p == 1:
print("printing A2[1]")
else:
print("printing A2[other]")
A = [A1, A2]
A[fselect]()
Nested functions are often confusing and unclear, and there is really no
need for them here. This does the same thing:
def A1(p):
print("printing", "A1[1]" if p==1 else "A1[other]"))
def A2(p):
print("printing", "A2[1]" if p==1 else "A2[other]"))
def fArray(fselect, fparm=1):
A = [A1,A2]
A[fselect](fparm)
In this example, I enclosed two functions within another function, and then put
those two functions in a list. Then, with appropriate parameters, I called one
of the functions in the list, associated the formal parameter with the function
in a call to the array, and presto, it performs the function.
The more advanced problem I wanted to solve, a two dimensional array of
functions, once this example is understood, becomes trivial to implement. In
fact, the more interesting problem I wanted to solve involved a dictionary of
functions in a two-dimensional array, and that too was easy to do in Python.
When I compare what this would require in C, C++, Java, or most other
languages, I find Python to be really easy for solving this kind of problem.
Next, I plan to develop the solution using decorators and assertions to empower
it with a greater level of portability and to make the functions more generic.
I hope someone finds this interesting.
Richard Riehle, PhD
--
https://mail.python.org/mailman/listinfo/python-list
