On 2015-05-21 23:20, John Pote wrote:
Hi everyone.
I recently had the problem of converting from an integer to its
representation as a list of binary bits, each bit being an integer 1 or
0, and vice versa. E.G.
0x53
becomes
[ 0, 1, 0, 1, 0, 0, 1, 1 ]
This I wanted to do for integers of many tens, if not hundreds, of bits.
Python very nicely expands integers to any size required, great feature.
Just wondered if there was a neat way of doing this without resorting to
a bit bashing loop.
Looking forward to some interesting answers,
John
I don't know how efficient you want it to be, but:
>>> number = 0x53
>>> bin(number)
'0b1010011'
>>> bin(number)[2 : ]
'1010011'
>>> list(map(int, bin(number)[2 : ]))
[1, 0, 1, 0, 0, 1, 1]
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