On 19.05.2015 19:01, Cecil Westerhof wrote:
> At the moment I am playing with things like:
> p = subprocess.Popen('ls -l', shell = True, stdout = subprocess.PIPE)
>
> I think that most of the times this are the values I want. So it would
> be nice to overrule the defaults. What is the best way to do this? I would like to answer with a counter-question: Why do you want to do this? What is the reason to use ls -l if you could also be using os.listdir() or os.scandir()? There are some reasons against screenscraping `ls` (locale-specifities and environment variable dependencies of ls) and using shell=True (with shells being huge complex beasts which may have unexpected security issues, see Shellshock), so I’m not sure why you would want to do that. regards, jwi
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