On 04/30/2015 06:35 PM, Seymore4Head wrote:
On Thu, 30 Apr 2015 22:00:17 +0200, Thijs Engels
<th...@buckazoids.com> wrote:
round(65253, -3)
might be what you are looking for...
On Thu, Apr 30, 2015, at 21:49, Seymore4Head wrote:
I have this page book marked.
https://mkaz.com/2012/10/10/python-string-format/
I am getting numbers from sixty thousand to two hundred thousand.
I would like to round them to the nearest thousand.
So 65,253 should read 65,000.
How?
Total=2100
for x in range (10,35):
count=1000/x
print ("Foo {:7,.0f} Fighters".format(Total*count))
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Thanks
I know there are more than one way to round and answer. I was hoping
that using the {:7,.0f} formatting had a solution.
There are definite tradeoffs, but since you're rounding to integer size,
the round() function works fine. If you wanted tenths, you'd have to
realize that a float (which is binary float) can't represent them
exactly. So depending on what further processing you do, you might see
some effects that would not seem like it worked right.
Using the % or the .format style of formatting works fine, but it gives
you a string. You didn't specify that, so people probably assumed you
wanted numbers.
--
DaveA
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