Dave Angel <da...@davea.name> writes: >> if x < 1e9: > Now 10**9 is way below either limit of floating point.
The idea was just to get rid of the case where c (further down in the code) ends up being a negative number. Floating point works fine for numbers that small. > And I can't figure out your code at this hour of night, but it's much > more complicated than Newton's method would be anyway. What I posted is just straightforward arithmetic. I'd expect Newton's method to be more complicated if you want to bound the error carefully and make sure it is non-negative. Maybe I'm wrong about that though. Note my comment "d is between 10 and 11" is slightly inaccurate. d can in some cases be slightly above 11 but that is fine. -- https://mail.python.org/mailman/listinfo/python-list
