Me:
> Here's a clever, though not (in my opinion) elegant solution
...
> This seems a bit more elegant, though the "replace" dictionary is
> still a bit of a hack
Here's the direct approach without using itertools. Each list is
iterated over only once. No test against a sequence element is ever
made (either as == or 'is') and the end of the sequence exception
is raised only once per input iterator.
The use of a list for the flag is a bit of a hack. If the list has
1 element then its true, no elements then its false. By doing it this
way I don't need one extra array and one extra indexing/enumeration.
def zipfill(*seqs):
count = len(seqs)
seq_info = [(iter(seq), [1]) for seq in seqs]
while 1:
fields = []
for seq, has_data in seq_info:
if has_data:
try:
fields.append(seq.next())
except StopIteration:
fields.append(None)
del has_data[:]
count -= 1
else:
fields.append(None)
if count:
yield fields
else:
break
Hmm, it should probably yield tuple(fields)
Andrew
[EMAIL PROTECTED]
--
http://mail.python.org/mailman/listinfo/python-list
