On 03/02/2015 01:38 PM, Charles Heizer wrote:
Sorry,
sortedlist = sorted(mylist , key=lambda elem: "%s %s" % (elem['name'],
LooseVersion(elem['version'])), reverse=True)
This is what I was trying but LooseVersion() was not sorting version numbers like I thought it
would. You will notice that Chrome version "40.0.2214.111" is higher than
"40.0.2214.91" but in the end result it's not sorting it that way.
Please don't top-post. put your remarks after whatever quoting you do.
You still haven't posted your LooseVersion() function source. I agree
with Emile that it's likely to be the problem.
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DaveA
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