On 02/20/2015 12:51 AM, Jason Friedman wrote:
I'd still advise using my_list.sort() rather than sorted(), as you
don't need to retain the original.
Hmm.
Trying to figure out what that looks like.
If I understand correctly, list.sort() returns None.
What would I return to the caller?
return_list = ....
return_list.sort(key=..., reverse = True)
return return_list
Oops, guess I'm not really returning a list, I'm returning an iterator.
Now you'll be returning a list, I believe.
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DaveA
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